Question

Some birds are sitting in an oak tree. Ten more birds land. More birds arrive until there are a total of four times as many birds as the oak tree had after the ten landed. A nearby maple tree has sixteen fewer than twelve times as many birds as the oak tree had after the ten landed. If both trees now have the same number of birds, how many birds were originally in the oak tree before the first 10 landed

Answer 1

Answer:

there must be 4 birds on the oak tree

Answer 2

There is a slight change in the question , the correct question is -

Q) Some birds are sitting in an oak tree. Ten more birds land. More birds arrive until there are a total of four times as many birds as the oak tree had after the ten landed. A nearby maple tree has sixteen fewer than twelve times as many birds as the oak tree had BEFORE the ten landed. If both trees now have the same number of birds, how many birds were originally in the oak tree before the first 10 landed.

ANS:

There were 7 birds on the oak tree before the 10 landed.

Solution:

• Let the number of birds sitting on the oak tree be x.

• Now ten more birds landed on the tree.Therefore birds on the tree becomes x+10.

• More birds arrive until it becomes equal to 4 times the birds on the oak tree after the ten landed.Number of trees on the tree becomes 4(x+10).

• Now on a nearby maple tree there are 16 less than 12 times the number of birds on the oak tree before the 10 landed.

• Now the number of birds on both the trees are equal.

• The equation becomes,

12x - 16 = 4(x+10)

12x - 16 = 4x + 40

8x = 56

x=7

• There were 7 birds on the oak tree before the 10 landed.