Question

Some candies were brought at 11 for 10r.s and the same number of candies at 9 candies for 10r.s ( First find the cost of 11 candies in this equation) . If all the number of candies are sold at 1r.s each find the loss % or gain %






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Answer 1

total candies brought =198

S.P 9f 198 candies =198r.s

C.P of 198 candies =200

loss% = 2/198×200

=2%

loss=2%

HOPE this HELPS you

Answer 2

Answer:

Step-by-step explanation:

In first condition,

C.P. of 11 candies= ₹10

C.P. of 1 candy=₹10/11

In second condition,

C.P. of 9 candies= ₹10

C.P. of 1 candy= ₹10/9

C.P. of both the candies=₹(10/11+10/9)

                                         =₹(90+110/99)

                                         =₹200/9

C.P.  of 1 candy=₹(200/9*1/2)

                         =₹100/99

S.P. of 1 candy=₹1

Loss=₹(100/99-1)=₹1/99

Loss%=(1/99)/(11/99)*100%

         =1% loss

HOPE THIS ANSWER SOLVED YOUR PROBLEM