Question

Some families with 2 children were surveyed and the following dates were recorded . 0,1,2. 184,714,425. If a family is chosen at random. compute the probability that it has 1) exactly 1 girl 2) exactly 2 boys​

Answer 1

Answer:

Here

probability of exactly one girl will be

total number of families= 111+375+714

1200

then probability = 714/1200

probability of exactly 2 boys= 111/1200

Answer 2

Concept:

The ratio of the number of favourable outcomes to the total number of outcomes of an event is known as probability.

Given:

The number of families having $0$ girls is $184$.

The number of families having $1$ girl is $714$.

The number of families having $2$ girls is $425$.

Find:

The probability of getting $1$ girl and also $2$ boys.

Solution:

Total number of families $= 184+714+425$

                                          $= 1323$.

(1) The probability of exactly 1 girl is $=\frac{714}{1323}$.

(2) The probability of exactly 2 boys is $=\frac{184}{1323}$.

Hence, the probability of exactly 1 girl is $\frac{714}{1323}$. The probability of exactly 2 boys is $\frac{184}{1323}$.