some fruits are sliced and packed into cylindrical cans of height 32 cm and diameter of base 20 cm. A label is placed around the curved surface of the can by leaving a margin of 2 cm from the top and bottom of the can. Find the surface area of the label.
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the margin of label is 2 CM from top and 2 CM from bottom
it means 4 CM less from the height of cylindrical cans
the height of label = 32-4 = 28 CM
length of the label is equal to the surface area of the cylindrical can
length of label = 2πr = 2π(d/2)
= 2 (π)(20/2) = 20π CM
so, length of one side of label = 28 CM
and,
another side = 20π CM
the surface area of label is length *breadth
area = 28 * 20π
= 560π CM sq.
it means 4 CM less from the height of cylindrical cans
the height of label = 32-4 = 28 CM
length of the label is equal to the surface area of the cylindrical can
length of label = 2πr = 2π(d/2)
= 2 (π)(20/2) = 20π CM
so, length of one side of label = 28 CM
and,
another side = 20π CM
the surface area of label is length *breadth
area = 28 * 20π
= 560π CM sq.
Answered by
3
Answer:
Step-by-step explanation:
the margin of label is 2 CM from top and 2 CM from bottom
it means 4 CM less from the height of cylindrical cans
the height of label = 32-4 = 28 CM
length of the label is equal to the surface area of the cylindrical can
length of label = 2πr = 2π(d/2)
= 2 (π)(20/2) = 20π CM
so, length of one side of label = 28 CM
and,
another side = 20π CM
the surface area of label is length *breadth
area = 28 * 20π
= 560π CM sq.
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