Question

some help would be good​

Answer 1

Answer:

14.75 sq. units

Step-by-step explanation:

$y = \sqrt{36 - {x}^{2} } \\ \\ area = ∫y \: dx$

$= ∫ \sqrt{36 - {x}^{2} } dx \\ \\ = ∫ {( \sqrt{36 - {x}^{2} } )}^{ \frac{1}{2} } dx$

$= \frac{3}{2} { \sqrt{36 - {x}^{2} } }^{ \frac{3}{2} }$

$area = {\sqrt[4]{36 - {x}^{2} }}^{3}$

$= \frac{3}{2} {\sqrt[4]{36 - {6}^{2} }}^{3} - \frac{3}{2} {\sqrt[4]{36 - {4}^{2} }}^{3} \\ \\ = 0 - \frac{3}{2} {\sqrt[4]{20 }}^{3} = - \frac{3}{2} {(2.11)}^{3}$

$= - \frac{3}{2} (9.45) \\ \\ = - 14.75 \: \: {unit}^{2}$

Thus, magnitude of area is 14.75