Question

Some hot water is added to three times its mass of cold water at 10°C. The
resulting temperature is found to be 20°С. Find the initial temperature of hot
water​

Answer 1

Mass of hot water = M.  let its temperatur be T  deg C

mass of cold water = 3 * M    three times mass of hot water.

cold water is at 10 deg C

final temperature = 20 C

  So WRITE equation for balancing the Heat energy

       M T  + 3M 10  =  (M + 3M) 20

     = M T + 30 M  =  4M * 20 = 80 M          cancel M

     T + 30 = 80            T = 50 deg Centigrade

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