Some ideal monoatomic gas A in an enclosure has a pressure P and the temparature T. Another ideal monoatomic gas B enclosed in a container of the same volume has a pressure 2P and temparature T/2. the ratio of average kinetic energy of molecule of gas A to gas B is
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Given :
Temperature of gas A, Ta = T
Temperature of gas B, Tb = T/2
To find :
The ratio of the average kinetic energy of molecule of gas A to gas B.
Solution :
Average kinetic energy = (3/2) * k * (temperature)
average kinetic energy of gas A = (3/2) * k * T
average kinetic energy of gas B = (3/2) * k * (T/2)
ratio of the average kinetic energy of gas A to gas B
= [ (3/2) * k * T ] / [ (3/2) * k * (T/2) ]
= 2 : 1
The ratio of the average kinetic energy of molecule of gas A to gas B is 2:1 .
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