Question

some important points and formulae of chapter HEAT AND THERMODYNAMICS....for IIT JEE level...​

Answer 1

Answer:

DQ=DU+DW first law

DQ=nCpdT at constant pressure

=nCvdT at constant volume

DW=pdV

in adiabatic process DW=0

freedom of gas

monoatomic=3

diatomic=5

polyatomic=7 at low temperatures 8-9 in high temperatures

Cp-Cv=r

r=8.31J (gas constant)

$\gamma = 1 + f \div 2 \: \: wheref \: is \: freedom \: ofgas$

$cp \div cv = \gamma$

hope this is helpful

Answer 2

Explanation:

DQ=DU+DW first law

DQ=nCpdT at constant pressure

=nCvdT at constant volume

DW=pdV

in adiabatic process DW=0

freedom of gas

monoatomic=3

diatomic=5

polyatomic=7 at low temperatures 8-9 in high temperatures

Cp-Cv=r

r=8.31J (gas constant)

\gamma = 1 + f \div 2 \: \: wheref \: is \: freedom \: ofgasγ=1+f÷2wherefisfreedomofgas

cp \div cv = \gammacp÷cv=γ

hope this is helpful