Question

Some kids, each of them with several toys, are playing in a room. The information about the kids and the number of toys they ha below i) Danny and Rick are brothers and they both have a total of 34 toys. i) Andrew has nine more toys than Mary does. i) The number of Lisa's toys is five more than Danny's. iv) The number of Nina's toys is half the sum of the number of Mary's and Lisa's toys. v) The combined number of Andrew's and Mary's toys is 25. vi) Andrew has five more toys than Danny does. On the basis of the given information, calculate the total number of toys that Danny has? O 11 13 14 15 18

Answer 1

Answer:

14

Step-by-step explanation:

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Answer 2

Given:

No. of toys Danny and Rick have = 34

No. of toys Andrew has = 9 + No. of toys with Mary

No. of toys Lisa has = 5 + No. of toys with Danny

No. of toys Nina has = 0.5(No. of toys with Mary + No. of toys with Lisa)

No. of toys with Andrew and Mary = 25

No. of toys with Andrew = 5 + No. of toys with Danny

To find:

No. of toys with Danny.

Solution:

Let no. of toys that Danny, Rick, Andrew, Mary, Lisa, and Nina be $D,R,A,M,L,N$

Then, on formulating the given information:

$D+R=34...(1)$

$A=9+M...(2)$

$L=5+D...(3)$

$N=\frac{1}{2}(M+L)...(4)$

$A+M=25...(5)$

$A=5+D...(6)$

From equations (2) and (5),

$A+M=25$

$A=9+M$

$9+M+M=25$

$2M=25-9=16$

$M=\frac{16}{2}=8$

∴ $A=9+M=9+8=17$

From equation (6),

$A=5+D$

$17=5+D$

$D=17-5=12$

Hence, Danny has 12 toys in total. Thus, the first option is correct.

Danny has 12 toys in total. The first option is the correct answer.