Some liquid is filled in a cylindrical vessel of radius r. Let f1 be the force applied by the liquid on the bottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section of side r. Let f2 be the force applied by the liquid on the bottom of this new vessel. Then
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# Answer- F2=F1/π.
# Explaination-
In the given situation, weight of liquid is constant.
So the pressure exerted by liquid in both beakers will be same.
P1=P2
For cylindrical container P1=F1/A1=F1/πr^2
For cuboidal container P2=F2/A2=F2/r^2
F1/A1=F2/A2
F1/πr^2=F2/r^2
F1/π=F2
F2=F1/π
Force exerted by liquid in cuboidal container will be F1/π.
# Answer- F2=F1/π.
# Explaination-
In the given situation, weight of liquid is constant.
So the pressure exerted by liquid in both beakers will be same.
P1=P2
For cylindrical container P1=F1/A1=F1/πr^2
For cuboidal container P2=F2/A2=F2/r^2
F1/A1=F2/A2
F1/πr^2=F2/r^2
F1/π=F2
F2=F1/π
Force exerted by liquid in cuboidal container will be F1/π.
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