Question

some measure are given in the adjacent figure find the area of the quadrilateral ABCD

Answer 1

ar (ABD)=1/2×40m×9m
=180m^2
ar (DBC)=1/2×13m×60m
=390m^2
ar (ABCD)=ar (ABD)+ar (DBC)
=180m^2+390m^2
=570m^2

Answer 2

Answer:

In ∆ABD,

Base = 9m

Height = 40m

Area of ∆ABD =1/2×base×height

= 1/2 ×9 × 40sq.m

= 180 sq.m

Area of ∆BCD =1/2×base×height

= 1/2 ×13 × 60sq.m

= 390 sq.m

Area of quadrilateral ABCD = Area of ∆ABD + Area of ∆BCD

=

180sq.m+390sq.m

= 570 sq.m