some of three prime number is 102. if one of them exceed other by 42 then one number is
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Answer:
Let X+Y+Z= 102
solution ;
Z=67
Z- 42=Y So Y=25
X= 102–(Y+Z)
X= 102 — (67+25)
X= 102 -92
X=8
∴X=8 Y= 25 Z= 67
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