Some of two number is 95. If one exceed other by 3.find the number
Answers
Answered by
5
Answer:
Let the two numbers be x and y, where y > x
Also given that, y - x = 3
=> y = 3 + x
=> x + y = 95
=> x + ( 3 + x ) = 95
=> 2x + 3 = 95
=> 2x = 95 - 3
=> 2x = 92
=> x = 46
=> y = x + 3 = 46 + 3 = 49
Hence the numbers are 46 and 49.
Answered by
7
:
Given:
Sum of two numbers is 95.
one number exceeds other by 3.
Let,
one number be x
another number = (x + 3)
So,
=> x + x + 3 = 95
=> 2x = 95 - 3
=> 2x = 92
=> x = 92 ÷ 2
=> x = 46
Hence,
one number (x) = 46
and another number (x + 3) = 46 + 3 = 49
Given:
Sum of two numbers is 95.
one number exceeds other by 3.
Let,
one number be x
another number = (x + 3)
So,
=> x + x + 3 = 95
=> 2x = 95 - 3
=> 2x = 92
=> x = 92 ÷ 2
=> x = 46
Hence,
one number (x) = 46
and another number (x + 3) = 46 + 3 = 49
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