some one help ill mark the person as a brainliest
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answer later
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P IS THE MIDPOINT OF AB
PQ IS PARALLEL TO BC AS PBCQ IS A TRAPEZIUM.
THEREFORE Q IS THE MIDPOINT OF AC.& PQ IS HALF OF BC
( BY MIDPOINT THEOREM )
PERIMETER = SUM OF ALL THE SIDES
THEREFORE PERIMETER OF TRAP. PBCQ= PQ+ QC + CB+ BP
AB =9.6 & P IS THE MIDPOINT OF AB
THEREFORE PB= 9.6/2=4.8 & PQ = 11/2= 5.5& QC=10.2/2
PQ+QC+CB+BP=5.5+5.1+11+4.8=26.4
HENCE PERIMETER OF TRAPEZIUM IS 26.4 cm
PQ IS PARALLEL TO BC AS PBCQ IS A TRAPEZIUM.
THEREFORE Q IS THE MIDPOINT OF AC.& PQ IS HALF OF BC
( BY MIDPOINT THEOREM )
PERIMETER = SUM OF ALL THE SIDES
THEREFORE PERIMETER OF TRAP. PBCQ= PQ+ QC + CB+ BP
AB =9.6 & P IS THE MIDPOINT OF AB
THEREFORE PB= 9.6/2=4.8 & PQ = 11/2= 5.5& QC=10.2/2
PQ+QC+CB+BP=5.5+5.1+11+4.8=26.4
HENCE PERIMETER OF TRAPEZIUM IS 26.4 cm
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