Question

some one help me out​

Answer 1

Answer:

Option (1)

Note:

• The first derivative of the equation of any curve give the slope of the tangent.

ie; slope of tangent = dy/dx.

• The first derivative of the equation at a particular point will give the slope of the tangent at that particular point.

• The product of slopes of two mutually perpendicular lines is -1.

• For any curve,

(slope of tangent)(slope of normal)= -1

OR

slope of normal = -1/slope of tangent

OR

slope of normal = -1/(dy/dx) = -(dx/dy)

• The Point-slope form of a straight line is given by ; m = (y-y1)/(x-x1)

where, "m" is the slope of the straight line and (x1,y1) is the given point which lies on that line.

• The slope, y-intercept form of a straight line is given by ; y = mx + c

where , "m" is the slope of the straight line and "c" is the y-intercept of that line.

{ for explaination, please refer to theattachments }