Question

Some one help me please....its really urgent and important...

Five years ago a man was 7 times as old as his son. Five years hence the father would be three times as old as his son. Find their present ages.

Answer 1

Present ages are x+5 and 7x+5

Future age of son = x+10

Future age of father = 7x+10

Given

7x+10 = 3*(x+10)

7x+10 = 3x+30

7x-3x = 30-10

4x = 20

x = 20/4

x = 5

7x = 7*5=35

x+5 =5+5= 10

7x+5 =7*5+5= 40

Answer 2

check out

i tried my best