Question

Some patients participated in a clinical trial for a new drug to treat osteoporosis . A patient is selected at random . The probability that the patient had no change in his bone mass density is 7/13 , the probability that he had a slight reduction in his bone mass density is 1/k and the probability that he had a significant reduction in his bone mass density is 1/2k
Find the value of k.
I ALREADY KNOW VALUE OF K, SO PLEASE ANSWER QUESTION WITH STEP BY STEP EXPLANATION. ​

Answer 1

Answer:

k=39/12

Step-by-step explanation:

sumof all probability=1

therefore,

7/13+1/k+1/2k=1

(14k+26+13)/26k=1

39+14k=26k

39=26k-14k

12k=39

k=39/12

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