some resistors each of 10ohm is connected in series and connected with a power supply of 220 volt and current in circuit is 0.2ampere . find the number of resistors......
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Answered by
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Here u go.....
R(1) = 10 ohm
R(2)= 15 ohm
R(3) = 20 ohm
V(2) = 3v
I = V/R
=3/15 = 0.2A
Since current in series circuit across each resistor remains same,
I = 0.2
Now,
R(1) = 10ohm
I = 0.2 A
V = I R
= 0.2(10) = 2 v.
Hence, current across circuit is 0.2 A and potential drop across 10 ohm resistor is 2v
4.5
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HELLO THIS is your answer
Since resistors are connected in series effective resistance of the circuit= 10+15+20=45ohm
Now in series connection same current flows through each resistor
Therefore current in circuit => V=IR
3=I×15
I= 3/15= 0.2A
Now potential difference across 10ohm resistor=> V=IR = 0.2×10 = 2V
Hope it helps.......
4.6
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