Chemistry, asked by parii47, 3 months ago

some salts can be made by titration.

In a titration experiment, 20.0 cm of aqueous sodium hydroxide reacts exactly with 25 cm of 0.100 mol/dm dilute sulfuric acid to make sodium sulfate.

2NAOH(aq) + H,SO,(aq) Na,so.(aq) 2H,0()

(1) Circle the name of the type of reaction that takes place

decomposition

neutralisation

precipitation

reduction

(1)

(ii) Calculate the concentration of the aqueous sodium hydroxide in g/dm using the following steps

Calculate the number of moles of dilute sulfuric acid used​

Answers

Answered by prasanpatel76
0

Answer:

sorry I didn't know your answer

Answered by freshestmajesty2
0

Answer:

first calculate for the number of moles for dilute sulfuric acid used

so n=c*v

n=0.01*0.025

=2.5*10 raise the power -3

second determine the number pf moles for hydroxide which react with dilute sulfuric acid

so mole ratio

1/2 *2.5*10 raise the power -3

=1.2*10 raise the power -3

now calculate the concentration of the aqueous sodium hydroxide in mol/dm cube

c=m/v

=1.25*10 raise the power -3/0.02

=0.0625

now you will calculate the concentration of the aqueous sodium hydroxide in g/dm cube

so c=n/v

0.0625/24

=2.6*10 raise the power -3

and that is th answer thank you

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Explanation:

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