Some school children went on an excursion
by a bus to a picnic spot at a distance of
300 km. While returning, it was raining and
me bus had to reduce its speed by 5 km/hr and
it took two hours longer for returning. Find the
time taken to return.
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Answer: Time for onward
journey=300/X.
Return Journey=300/X-5
3oo/x-5-3oo/x=2
300x-3oo(x-5)=2(x-5) x
300x-300x +1500 = 12x^2-10x
1500 = 2x^2-10x
2x^2-10x-1500 =o
x^2-5x-750=0
(x-30) (x +25)=0
x=30
Time taken to return
= 300/X-5=300/25=12hrs
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