Math, asked by jaiswalviva, 2 months ago

some sum of every row column and diagonal is 3 complete magic square ​

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Answered by XxAKHILROYxX
2

Step-by-step explanation:

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Answered by lucky099
0

\bold{\dfrac{2^{x}+(22)^{x}+(222)^{x}}{3^{x}+(33)^{x}+(333)^{x}}=\dfrac{9}{4}   } 

\bold{\dfrac{2^{x}+(22)^{x}+(222)^{x}}{3^{x}+(33)^{x}+(333)^{x}}=[\dfrac{4}{9}]^{-1} } 

\bold{\dfrac{2^{x}(1+11^{x}+111^{x})}{3^{x}(1+11^{x}+111^{x})}=((\dfrac{2}{3})^{{{2}}})^{{{-1}}}   } 

\bold{\dfrac{2^{x}\cancel{(1+11^{x}+111^{x})}}{3^{x}\cancel{(1+11^{x}+111^{x})}}=(\dfrac{2}{3})^{-2}   } 

\bold{\dfrac{2^{x}}{3^{x}}=(\dfrac{2}{3})^{-2}   } 

\bold{(\dfrac{2}{3})^{x} =(\dfrac{2}{3})^{-2}   } 

\bold{ x=-2  }

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