Question

Some the equations
(2x+3) (x-4) =6​

Answer 1

$\huge\underline\mathscr{SOlution}$

$\sf (2x+3)(x-4)=6$

$\sf x(2x+3)-4(2x+3)=6$

$\sf 2x^2+3x-8x-12=6$

$\sf 2x^2-5x-12=6$

$\sf 2x^2-5x=12+6$

$\sf 2x^2-5x-18=0$

$\sf 2x^2+4x-9x-18=0$

$\sf 2x(x+2)-9(x+2)=0$

$\sf (2x-9)(x+2)=0$

Either

x = 9/2

or

x = -2

Answer 2

$\huge\mathbb{SOLUTION}$

= (2x+3)(x-4) = 6

= x(2x+3)-4(2x+3) = 6

= 2x²+3x-8x-12 = 6

= 2x²-5x= 6+12

= 2x²-5x = 18

= 2x² - 5x - 18 = 0

= 2x² +4x-9x-18 =0

= 2x(x+2)-9(x+2) = 0

= (x+2)(2x-9) = 0

Hence

x = -2

or

x = 9/2