Question

Some toffee or bought at six for rupee and the same number at four for a rupee lf the whole lot is sold at 5 for a rupee find the gain or loss percent

Answer 1

$\huge\underline\mathtt\red{Solution}$

Make these sentences into negative:-

➛ Let the total number of toffees be ‘x’

Given,

cost price of 11 toffees is = Rs 10 Cost price of 1 toffee is = Rs 10/11

Given,

cost price of 9 toffees is = Rs 10 Cost price of 1 toffee is = Rs 10/9

When equating both the costs we get,

Cost price of two toffees = (10/11) + (10/9) = (90 + 110)/99 = 200/99

Cost price of one toffee is = (Rs 200/99)/2 = Rs 200/198

We know that selling price of 1 toffee

(Given) =

Rs 1 Loss = CP – SP = 200/198 – 1 = (200-198)/198 = 2/198

Loss% =

(loss/cost price) × 100 = (2/198)/(200/198) × 100 = 2/198 × 198/200 × 100 = 2/200 × 100 = 2/2 = 1%

∴ It is 1% loss on the whole truncation.

Hence, Proved

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$\sf\red{Thank\:you!}$

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Answer 2

${\huge{\pink{↬}}} \:  \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

Make these sentences into negative:-

➛ Let the total number of toffees be ‘x’

Given,

cost price of 11 toffees is = Rs 10 Cost price of 1 toffee is = Rs 10/11

Given,

cost price of 9 toffees is = Rs 10 Cost price of 1 toffee is = Rs 10/9

When equating both the costs we get,

Cost price of two toffees = (10/11) + (10/9) = (90 + 110)/99 = 200/99

Cost price of one toffee is = (Rs 200/99)/2 = Rs 200/198

We know that selling price of 1 toffee

(Given) =

Rs 1 Loss = CP – SP = 200/198 – 1 = (200-198)/198 = 2/198

Loss% =

(loss/cost price) × 100 = (2/198)/(200/198) × 100 = 2/198 × 198/200 × 100 = 2/200 × 100 = 2/2 = 1%

∴ It is 1% loss on the whole truncation.

Hence, Proved

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