Question

Some workers are painting a hall with length, breadth and height of 35 m, 50 m and 8 m respectively. If they can paint 10 sq.m area from one liter of paint, find the amount of paint required to paint the walls and ceiling of the hall

Answer 1

Answer:

Area to be painted = area of the walls + area of ceiling

=2(hl+hb)+lb

= 2×(8×35+8×50)+35×50=2710msq

No. of cans required =

100

2710

=27.1

Hence, 27.1 cans are required to paint the walls and the ceiling of the cuboidal hall.