Somebody help me with explanation.
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Answer is d.
.
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Any how...what ever the value of x be.. Cotx =1/tanx so Cot(x/2)=1/tan(x/2).
.
Thus tan(x/2).cot(x/2)
= tan(x/2) × 1/tan(x/2)
= 1
.
.
Any how...what ever the value of x be.. Cotx =1/tanx so Cot(x/2)=1/tan(x/2).
.
Thus tan(x/2).cot(x/2)
= tan(x/2) × 1/tan(x/2)
= 1
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