Question

Somebody help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Answer 1

Answer:

Is this Data Handling Chapter?

Answer 2

10) Total no. of marbles= 3+2=5

So, P(getting a blue marble)= 2/5

11) Total no. of bulbs=600

Defective bulbs=12

So, no. of non defective bulbs= 600-12=588

Therefore, P(getting a non defective bulb)= 588/600

12) Possible no. of outcomes= 6

(i) P(getting an even number)= 2/6=1/3

(ii) P(getting a multiple of 3)= 2/6=1/3

(iii) P(getting number 3 or 4)= 2/6=1/3

(iv) P(getting an odd number)= 3/6=1/2

(v) P(getting a no. b/w 3 and 6)= 2/6=1/3

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