Question

Somebody please solve this question ​

Answer 1

$External \: radius \: of \: the \: Sphere (R) = 6 \:cm$

$Thickness \: of \:the \: Sphere (w) = 1 \:cm$

$Internal \: radius \: of \: the \: Sphere (r)\\ = (R-w )\:cm\\= (6-1)\\= 5 \:cm$

/* According to the problem */

/* Hallow sphere melted and cast into a sphere*/

$Radius \: of \: the \: cylidercal \:bar = 2 \:cm$

$Let \:Height \: of \: the \: cylider = \red{h \:cm }$

$Volume_{\blue{(cylider)}} = Volume_{\pink{(Hallow \: sphere)}}$

$\implies \pi (radius)^{2} \times h = \frac{4}{3} \pi (R^{3} - r^{3} )$

$\implies 2^{2} \times h = \frac{4}{3} \times ( 216-125)$

$\implies h = \frac{4 \times 91 }{3 \times 4 }$

$\implies h = \frac{ 91 }{3 }$

$\implies h = 30.33 \:cm$

Therefore.,

$\red{ \:Height \: of \: the \: cyliderival \:bar } \green {= 30.33 \:cm }$

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Answer 2

Answer:

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