Question

someone answer the above

Answer 1

Actually this is a similar answer

◆ Answer-

ρ = 8.8×10^-6 ohm-m

◆ Explaination-

# Given-

R = 35 ohm

L = 2 m

r = 0.4 mm = 4×10^-4 m

T = 30 °C

# Solution-

Resistivity of the material is given by the formula -

ρ = RA / L

ρ = Rπr^2 / L

ρ = 35×3.142×(4×10^-4)^2 / 2

ρ = 8.8×10^-6 ohm-m.

Therefore, resistivity of given metal wire at 30 °C is 8.8×10^-6 ohm-m.

Hope this helps...

Answer 2

I hope you understand...

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