Question

someone do it class 8 exponents and power​

Answer 1

Answer:

$\frac{49\times x^{-2}}{7^{-3}\times 14\times x^{-4}}=\frac{7^{4}\times x^{2}}{2}$

Step-by-step explanation:

$\frac{49\times x^{-2}}{7^{-3}\times 14\times x^{-4}}$

$= \frac{7^{2}\times x^{-2}}{7^{-3}\times 2\times 7^{1}\times x^{-4}}$

$= \frac{7^{2+3-1}\times x^{-2+4}}{2}$

$By\: exponential \:law,\\\boxed {\frac{a^{m}}{a^{n}}=a^{m-n}}$

$= \frac{7^{4}\times x^{2}}{2}$

Therefore,

$\frac{49\times x^{-2}}{7^{-3}\times 14\times x^{-4}}=\frac{7^{4}\times x^{2}}{2}$

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Answer 2

Answer:

Step-by-step explanation: