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first term= a = 5
sum of first four terms = 4/2[2(5)+(4-1)d]
2(10+3d)= 20+6d
sum of next four terms= sum of first eight terms - sum of first four terms
4(10+7d) - 20-6d
according to ques
20+6d = 1/2[ 40+28d - 20-6d]
20+6d = 10+11d
10 = 5d
d= 2
common difference is 2
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