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answer for the given problem is given
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(1)12a^3-9a^2+4a-3=3a^2(4a-3)+4a-3=(4a-3)(3a^2+1)
(2)2p^3+5p^2+6p+16=p^2(2p+5)+3(2p+5)=
(2p+5)(p^2+3)
(3)3n^3-4n^2+9n-12=n^2(3n-4)+3(3n-4)=(3n-4)(n^2+3)
(4)12n^3+4n^2+3n+2=4n^2(3n+1)+3n+1=(3n+1)(4n^2+1)
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