Someone help me with this please......it's really urgent!!
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what is the question?
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rincyroshan:
Ohhhhhh............
Five years ago man was 7 times as old as his son. Five years hence the father would be three times as old as his son. Find their present ages.
Present ages are x+5 and 7x+5
Future age of son = x+10
Future age of father = 7x+10
Given
7x+10 = 3*(x+10)
7x+10 = 3x+30
7x-3x = 30-10
4x = 20
x = 20/4
x = 5
7x = 35
x+5 = 10
7x+5 = 40
Future age of son = x+10
Future age of father = 7x+10
Given
7x+10 = 3*(x+10)
7x+10 = 3x+30
7x-3x = 30-10
4x = 20
x = 20/4
x = 5
7x = 35
x+5 = 10
7x+5 = 40
Thanks
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1
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what the hell is your question
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