Question

someone help plss, what's the area of the followings, with explanation, thx

Answer 1

1st triangle is a equilateral triangle and eecond is isosceles triangle.

$ar(triangle.1) = \frac{ \sqrt{3} }{4} {side}^{2} \\ = \frac{ \sqrt{3} }{4} \times 6.5 \times 6.5 \\ = \frac{ \sqrt{3} }{4} \times 65 \times 65 \times \frac{1}{100} \\ = \frac{ \sqrt{3} \times 4225}{4 \times 100} \\ = \frac{ \sqrt{3} \times 1056.25}{100} \\ = 10.5625 \sqrt{3} \: \: \: {inch}^{2} \\ ar(triangle.2) = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 5.4 \times \sqrt{(7.3) \times (7.3) - \frac{5.4}{2} \times \frac{5.4}{2} } \\ = 2.7 \times \sqrt{ {7.3}^{2} - {2.7}^{2} } \\ = sorry \: bro \: you \: have \: to \: calculate \: this \: by \: calculator \: because \: i \: dont \: have \: pen \: right \: now.$