Question

someone online........
do this plz 28 and 29​

Answer 1

Answer:

$\huge \pink {\tt {28.}}$ $\purple {\tt {( {a}^{2} - {b}^{2} )( {c}^{2} - {d}^{2} ) - 4abcd}}$

$\purple {\tt { = {a}^{2} ( {c}^{2} - {d}^{2} ) - {b}^{2} ( {c}^{2} - {d}^{2} ) - 4abcd}}$

$\purple {\tt { = {a}^{2} {c}^{2} - {a}^{2} {d}^{2} - {b}^{2} {c}^{2} + {b}^{2} {d}^{2} - 4abcd}}$

$\huge \purple {\tt {29.}}$ $\pink {\tt { {4x}^{2} - 12ax - {y}^{2} - {z}^{2} - 2yz + {9a}^{2}}}$

$\pink {\tt {= {(2x - 3a)}^{2} - ( {y}^{2} + 2yz + {z}^{2} )}}$

$\pink {\tt {= {(2x - 3a)}^{2} - {(y + z)}^{2}}}$

$\pink {\tt {= (2x - 3a - (y + z)) \times (2x - 3a + (y + z))}}$

$\pink {\tt {= (2x - 3a - y - z) \times (2x - 3a + y + z)}}$