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sidra1784:
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(I) In ∆AOB and ∆ AOC,
AB=AC
AO=AO( common)
angle ABO = angle ACO
So,
triangle AOB= triangle AOC
OB=OC (by cpct)
(ii)angle BAO = angle CAO (by cpct)
so AO bisects angle A
AB=AC
AO=AO( common)
angle ABO = angle ACO
So,
triangle AOB= triangle AOC
OB=OC (by cpct)
(ii)angle BAO = angle CAO (by cpct)
so AO bisects angle A
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