Question

someone please answer me fast...​

Answer 1

Answer:

Let the terms be a,a+d,a+2d,a+3d,a+4d,a+5d.

It is given that the difference between the first and last term is 55, therefore,

a+5d−a=55

⇒5d=55

⇒d=

5

55

=11......(1)

It is also given that the sum of all terms is 345, therefore using equation 1 we have,

a+a+d+a+2d+a+3d+a+4d+a+5d=345

⇒6a+15d=345

⇒6a+(15×11)=345

⇒6a+165=345

⇒6a=345−165

⇒6a=180

⇒a=

6

180

=30

With a=30 and d=11, the 6 terms are as follows:

a=30

a+d=30+11=41

a+2d=30+(2×11)=30+22=52

a+3d=30+(3×11)=30+33=63

a+4d=30+(4×11)=30+44=74

a+5d=30+(5×11)=30+55=85

Hence, the terms are 30,41,52,63,74,85.

Step-by-step explanation:

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