Someone please send me step by step solution of this.
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Answer:
in ∆PQR and ∆SRQ
angle QPR=angle RSQ. (given 90°)
QR=QR. (common)
PR=SQ. (given)
so, ∆PQR=~∆SQR.
(by S-A-S congruence rule)
I hope it is helpful for you
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