Math, asked by anshika170908, 5 months ago

Someone please send me step by step solution of this. ​

Attachments:

Answers

Answered by mithleshkumarsharma6
1

Answer:

in ∆PQR and ∆SRQ

angle QPR=angle RSQ. (given 90°)

QR=QR. (common)

PR=SQ. (given)

so, ∆PQR=~∆SQR.

(by S-A-S congruence rule)

I hope it is helpful for you

Similar questions