Math, asked by diksha588, 1 month ago

Someone please solve this.​

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Answered by MissSolitary
3

 :  \longrightarrow \:  \underline{ \underline{{ \huge{ \mathfrak{R}}} \mathfrak{equired} \:  \:  \:  \:  { \huge{ \mathfrak{ A}}} \mathfrak{nswer :-}</p><p>}}

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 :  \longrightarrow \tt \:  \frac{2}{ {x}^{2} }   -  \frac{5}{x}  + 2 = 0,  \:  \:  \:  \:  \: x ≠ 0 \\  \\   \sf \:On \:  multiplying \:  both \:  sides \:  by \:  x², \\ :  \longrightarrow \tt \:   \cancel{{x}^{2}}  \times  \frac{2}{ \cancel{ {x}^{2}} }  -  {x}^{ \cancel{2}}  +  \frac{5}{ \cancel{x}}  + 2 \times  {x}^{2}  = 0  \times  {x}^{2} \\  \\  :  \longrightarrow\tt 2 - 5x + 2 {x}^{2}  = 0 \\  \\  :  \longrightarrow \tt \: 2 {x}^{2}  - 5x + 2 = 0 \\  \\  :  \longrightarrow \tt \:  2{x}^{2}  - 4x - x + 2 = 0 \\  \\  :  \longrightarrow \tt \: 2x(x - 2) - 1(x - 2) = 0 \\  \\  :  \longrightarrow \tt \: (x - 2)(2x - 1) = 0 \\  \\  \\   \rightarrow \tt \: x - 2 = 0 \\  \boxed{\tt \therefore \:  x = 2} \\  \\  \\    \rightarrow \tt \: 2x - 1 = 0 \\  \tt \: 2x = 1 \\ \boxed{   \tt \therefore \: x =  \frac{1}{2} }

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Answer :-

=> x = 2 or 1/2..

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@MissSolitary ✌️

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