Question

Someone please solve this fast. Thank you in advance........

Answer 1

Answer:

$\sqrt{ \frac{x}{3} } + 6 \sqrt{ \frac{3}{x} } = 5$

on Squaring both sides;

$( \sqrt{ \frac{x}{3} } + 6 \sqrt{ \frac{3}{x} } ) {}^{2} = 5 {}^{2}$

$\frac{x}{3} + \frac{108}{x} + 12 = 25$

$\frac{x}{3} + \frac{108}{x} = 13$

${x {}^{2} - 39x + 324} = 0$

x²–27x–12x+324=0

x(x–27)–12(x–27)=0

Therefore, x=12 or x=27