Math, asked by diksha588, 1 month ago

Someone please solve this problem.​

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Answers

Answered by singraghuveer23
1

GIVEN :

The equation is \frac{x^2}{15}-\frac{x}{3}-10=0

15

x

2

3

x

−10=0

TO SOLVE :

The given equation \frac{x^2}{15}-\frac{x}{3}-10=0

15

x

2

3

x

−10=0 by factorisation.

SOLUTION :

Given equation is \frac{x^2}{15}-\frac{x}{3}-10=0

15

x

2

3

x

−10=0

By solving the given equation \frac{x^2}{15}-\frac{x}{3}-10=0

15

x

2

3

x

−10=0 by factorisation.

\frac{x^2}{15}-\frac{x}{3}-10=0

15

x

2

3

x

−10=0

Multiply by 15 on both sides of the given equation we get,

x^2-5x-150=0x

2

−5x−150=0

The above equation x^2-5x-150=0x

2

−5x−150=0 can be written as below :

x^2-15x+10x-150=0x

2

−15x+10x−150=0

x(x-15)+10(x-15)=0x(x−15)+10(x−15)=0

By taking the common factors outside we get,

(x+10)(x-15)=0(x+10)(x−15)=0

∴ \frac{x^2}{15}-\frac{x}{3}-10=(x+10)(x-15)=0

15

x

2

3

x

−10=(x+10)(x−15)=0 .

∴ the given equation \frac{x^2}{15}-\frac{x}{3}-10==0

15

x

2

3

x

−10==0 is solved by factorisation is (x+10)(x-15)=0.

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