Question

Someone please tell me the ans ...It is so confusable ...
Anyone can clear it for me. .....
Please

I will mark the answer as brainliest

Answer 1

Answer:

$tan^{2} \alpha =sec^{2} \alpha -1\\ =(x+1/4x)^{2} -1\\=x^{2} +1/16x^{2} -1/2\\=(x-1/4x)^{2} \\tan\alpha =(x-1/4x)^{2} \\\\lhs=sec\alpha +tan\alpha \\=x+1/4x+x-1/4x\\=2x\\=rhs$

Step-by-step explanation:

Answer 2

plzz mark my answere as brainlist