Someone pls answer the 7th question sub-division C. With Explanation pls
Answers
Step-by-step explanation:
GMAT Club
FORUM
GMAT CLUB TESTS
QUESTION BANKS
MBA PROGRAMS
REVIEWS
DEALS & DISCOUNTS
CHAT
T&C AND PRIVACY POLICY
GMAT Club Rules
Login
Username
Password
Register Forgot password?
Close
Search
Close
GMAT Club Forum Index Problem Solving (PS)
What is the remainder when 3^24 is divided by 5? : Problem Solving (PS)
TAGS
Topic Discussion
Page 1 of 1
nycgirl212 Jun 8, 2016
00:00 ABCDE
DIFFICULTY: 5% (low) QUESTION STATS: based on 706 sessions
78% (00:53) correct
22% (01:03) wrong
What is the remainder when 3^24 is divided by 5?
A. 1
B. 2
C. 3
D. 4
Spoiler: OA
Kudos
2 kudos, 29 bookmarks
Most Helpful Community Reply
Senthil1981 Jun 8, 2016
Answer is B : 1
We can either use the Mod formula or since the question can be simplified, let's do that.
324324 can be simplified to 912912 and then to 816816. So if the last digit is 1 , then remainder of division by 5 will always be 1.
(Share a Kudos, if you like this explanation :-D )
Kudos
11 kudos, 7 bookmarks
General Discussion
Mbawarrior01 Jun 21, 2016
We can also use the following method :
Since the divisor is 5, the number that ends in 0 or 5 will be fully divisible. You can deduce the remainder utilising the units digit of the number.
Now, 3^24
Using the concept of cyclicity => 3^24 will have "1" in units digit.
Thus, 1/5 => Remainder is 1.
This concept may help when the power is a bigger number.
Step-by-step explanation:
heyy This is your homework then why you cheat ....