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Answers
Answer:
Step-by-step explanation:
6. Let the number of 10 rupee notes be x.
Let the number of 5 rupee notes be y.
Given, sum of 10 rupee notes and 5 rupee notes is equal to 190.
=> x * 10 + y * 5 = 190
=> 10x + 5y = 190 ----- (i)
Given, if number of notes interchange the sum is 185
=> y * 10 + x * 5 = 185
=> 10y + 5x = 185 --- (ii)
Multiply (i) by 2 and then subtract (ii) from it, to solve the equations.
20x + 10y = 380
5x + 10y = 185
- - -
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15x = 195
=> x = 195/15 = 13.
=> x = 13
Substitute value of x in any of (i) or (ii) to get y.
substituting in (i), 10 * 13 + 5y = 190
=> 5y = 190 - 130
=> 5y = 60
=> y = 12.
Thus the number of 10 rupee notes are 13.
the number of 5 rupee notes are 12.
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7. Since points (3, -1) and (6,1) lie on the line px + qy = 9, substituting these values in place of x and y should make L.H.S and R.H.S equal.
=> Substituting (3, -1), 3p - q = 9 --- (i)
=> Substituting (6,1), 6p + q = 9 --- (ii)
Now solve equations (i) and (ii) by addition.
3p - q = 9
6p+q = 9
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9p = 18
=> p = 18/9 = 2.
Substitute value of p in any of the equations.
substituting in (i), 3 * 2 - q = 9
=> 6 - q = 9
=> q = 6 - 9 = -3.
Thus the equation is 2x - 3y = 9.
Verification: Substitute the (3, -1 ) and (6,1) in place of x and y. The L.H.S of equation will be equal to R.H.S
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8. Let x and y be the two numbers.
Given, sum of two numbers divided by 15, quotient = 2, remainder = 10.
=> 15 * 2 + 10 = x + y
=> x + y = 40 ---- (i)
Given, difference of two numbers divided by 3, quotient = 4, remainder = 2.
=> 3 * 4 + 2 = x - y
=> x - y = 14 ---- (ii)
Solve equations (i) and (ii) by addition,
x + y = 40
x - y = 14
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2x = 54
=> x = 54/2 = 27.
Substitute value of x in any of the equations to get y.
Substituting in (i),
=> 27 + y = 40
=> y = 40 - 27
= 13.
Thus the numbers are 27 and 13.
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