someone pls prove it
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R.H.S.= sec 60° + tan 60°
L.H.S= Whole root of 1+cos 30°/ whole root of 1-cos 30°
=whole root of (1+ cos 30°)²/ sin²30°{multiplying by 1+cos 30°/1+cos 30°]
=1+ cos 30°/sin 30°
=cosec 30° + cot 30°
=sec 60° + tan 60° as sec A=cosec(90°-A) and tan A=cot (90°-A) ......
so, LHS=RHS[proved].......
Hope it helps....
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hii
dear
hear is your answer
i hope this answer help you
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