someone pls solve this!!!!
chapter- differentiation
if you don't know the answer pls don't reply!
Attachments:
Answers
Answered by
1
taking log both side
∴log(x^y.y^x)=log5
∴logx^y+logy^x=log5
∴ylogx+xlogy=log5
(dy/dx)logx+y/x +logy+(x/y)dy/dx=0
(dy/dx){logx+x/y} = - {logy+y/x}
dy/dx = -[{logy+y/x}/{logx+x/y}]
Answered by
0
Answer:
wrong
Step-by-step explanation:
try yourself no cheating
Similar questions