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Bro see it. It help u to solve
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Your answer is :-
mloecular mass of CO2 = 44u
molecular mass of N2O = 44u
°•° mixture contain CO2 and N2O in 2:5 by mass
Let, mixture contain 2x Gram CO2 and 5x Gram N2O.
44 g CO2 = 6.023×10^23 molecles
So, 2x Gram CO2 = 6.023×10^23/44)2x molecles
also,
44 Gram N2O = 6.023×10^23 molecles
So, 5x Gram N2O = 6.023×10^23/44)5x
•°• there ratio is
= 2:5
mloecular mass of CO2 = 44u
molecular mass of N2O = 44u
°•° mixture contain CO2 and N2O in 2:5 by mass
Let, mixture contain 2x Gram CO2 and 5x Gram N2O.
44 g CO2 = 6.023×10^23 molecles
So, 2x Gram CO2 = 6.023×10^23/44)2x molecles
also,
44 Gram N2O = 6.023×10^23 molecles
So, 5x Gram N2O = 6.023×10^23/44)5x
•°• there ratio is
= 2:5
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