Physics, asked by ayushthemaestro, 10 months ago

SOMEONE PLS SOLVE THIS THING CORRECTLY AND BRING THIS TO 2.017×10^20 form.
no spamming
first and Correct answer will be marked as BRAINLIEST
help​

Attachments:

Answers

Answered by CunningKing
3

\sf{\dfrac{6.67 \times 10^-^1^1 \times 6 \times 10^2^4 \times 7.4 \times 10^2^2}{3.84 \times 10^8 \times 3.84 \times 10^8} }

\displaystyle{\sf{=\frac{6.67 \times 6\times7.4 \times 10^{-11}\times10^{24}\times 10^{22}}{3.84 \times 3.84 \times 10^8 \times 10^8} }}\\\\\\\displaystyle{\sf{= \frac{296.148 \times 10^{-11+24+22}}{14.7456 \times 10^{8+8}} }}\\\\\\\displaystyle{\sf{= \frac{296148 \times 10^-^3 \times 10^3^5}{147456 \times 10^-^4 \times 10^1^6} }}\\\\\\\displaystyle{\sf{= \frac{296148 \times 10^{-3+35}}{147456 \times 10^{-4+16}} }}\\\\\\\displaystyle{\sf{= \frac{296148 \times 10^3^2}{147456 \times 10^1^2} }}\\\\\\

\displaystyle{\sf{= \frac{296148 \times 10^3^2 \times 10^-^1^2}{147456} }}\\\\\\\displaystyle{\sf{= \frac{296148 \times 10^{32-12}}{147456} }}\\\\\\\displaystyle{\sf{= \frac{296148  \times 10^2^0}{147456} }}\\\\\\\displaystyle{\sf{=2.008 \times 10^2^0}}

The calculation is correct, but the values are somehow different. Consider the approx. values :)

Similar questions