Question

Someone pls tell the answer​

Answer 1

Answer:

to prove: AE =to BE, TRIANGLE DAE IS EQUAL TO 15

proof: triangle EDC is equilateral triangle so

Step-by-step explanation:

de=ce tir ECDis equilateral triangle

DA=CB because ABCD is a square

so,

DA=CB

ED=EC

SO, AB=DC because equilateral triangle and square equilateral triangle all sides are equal and in a square all sides are equal so AB equel to DC

So,

AE=BE

Tri AED congruent to Tri BECBEC

because all sides are equal

to prove: angle DAE is 15 degree

proof: angle aed is 15 degree becauseequilateral triangle all sides are equal and in this triangle angle DEC is divied in to 3 parts angle DEC =15, angle aeb=15 and angle ebc is=30

in triangle aed angle aed =15

DA=DE SIDES ARE EQUAL

SO,angle DAE =15 degree because sides are equal so opposite angles are also equal

so,

angle DAE is equal to 15 degree

hence proved

MARK AS A BRAINLIST

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

In the adjoining figure, ABCD is a square and $\Delta EDC$ is an equilateral triangle. Prove that,

1. AE = BE.
2. $\angle DAE=15\degree$

$\star\:\:\:\bf\large\underline\blue{Proof:-}$

Since, ABCD is a square, therefore,

$AB=BC=CD=AD$.

Now, $\Delta DCE$ is an equilateral triangle.

So,

$DC=CE=DE$.

Also,

$\angle ADC=\angle BCD=90\degree\:\:.......(i)$.

And,

$\angle EDC=\angle DCE =60\degree\:\:.......(ii)$ /*Since $\Delta EDC$ is an equilateral triangle */

Combining equation (i) and (ii), we get,

$\angle ADE = \angle BCE$

In $\Delta AED$ and $\Delta BCE$.

1. $AD=BC$ (ABCD is a square)
2. $DE = EC$ (Sides of equilateral triangle).
3. $\angle ADE = \angle BCE$ (Proved earlier) .

Therefore,

$\Delta ADE \cong \Delta BCE$ (By SAS)

So,

• AE=BE (c.p.c.t) (Proved part (i))

Now,

ABCD is a square and sides of triangle DCE are equal to the sides of the square.

So,

AD=DE.

Therefore,

Triangle ADE is an equilateral triangle.

So,

$\angle DAE=\angle DEA$.

Now,

$\angle ADE=\angle ADC+\angle EDC$

$\implies \angle ADE = 150\degree$.

So,

$\angle DAE=\angle DEA=\frac{180\degree-150\degree}{2}=15\degree$.

Hence Proved.