someone plz answer only correct answer plz.....
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Yo
we can write this as
cosy=x
differentiating both side wrt x we get
-siny dy/dx=1
dy/dx=-cosecy
differentiating again wrt x we get
d²y/dx²=cosecy*coty* dy/dx
=cosecy*coty*(-cosecy)
=-coty*cosec²y
Hope this helps
Answered by
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answer for the given problem is given
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