Question

someone plz answer this question step by step ​

Answer 1

Answer:

13 m.

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Answer 2

Solution

Given :-

• Height of two poles 6 m and 11m
• Distance between their feet 12m

Find :-

• Distance between their top

Explanation

Let,

AB is first pole & CD is second pole there height be 6m & 11m ,

and,

Distance between BD is 12m ,

So,Now we ,

Drop a line AC and a other line AE in CD , parallel to BD.

So, by figure ,

• BD = AE = 12m
• AB = ED = 6m

And,

• CE = CD - ED

==> CE = 11 - 6 = 5 m

So we take a right ∆AEC,

Where,

• Hypotenuse = AC = ?
• Base = AE = 12m
• Perpendicular = CE = 5 m

Using Pythagoras's Theorem ,

★ (Hypotenuse)² = (Base)² + (perpendicular)²

==> AC² = 12² + 5²

==> AC² = 144 + 25

==> AC² = 169

==> AC = √169

==> AC = 13

Hence

• Distance between their top of pole will be AC = 13 m

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